Calculates variance based on the entire population (ignores logical values and text in the population).
Syntax
VAR.P(number1,[number2],...)
The VAR.P function syntax has the following arguments:
-
Number1 Required. The first number argument corresponding to a population.
-
Number2, ... Optional. Number arguments 2 to 254 corresponding to a population.
Remarks
-
VAR.P assumes that its arguments are the entire population. If your data represents a sample of the population, then compute the variance by using VAR.S.
-
Arguments can either be numbers or names, arrays, or references that contain numbers.
-
Logical values, and text representations of numbers that you type directly into the list of arguments are counted.
-
If an argument is an array or reference, only numbers in that array or reference are counted. Empty cells, logical values, text, or error values in the array or reference are ignored.
-
Arguments that are error values or text that cannot be translated into numbers cause errors.
-
If you want to include logical values and text representations of numbers in a reference as part of the calculation, use the VARPA function.
-
The equation for VAR.P is:
where x is the sample mean AVERAGE(number1,number2,…) and n is the sample size.
Example
Copy the example data in the following table, and paste it in cell A1 of a new Excel worksheet. For formulas to show results, select them, press F2, and then press Enter. If you need to, you can adjust the column widths to see all the data.
Strength |
||
1,345 |
||
1,301 |
||
1,368 |
||
1,322 |
||
1,310 |
||
1,370 |
||
1,318 |
||
1,350 |
||
1,303 |
||
1,299 |
||
Formula |
Description |
Result |
=VAR.P(A2:A11) |
Variance of breaking strengths for all the tools, assuming that only 10 tools are produced (the entire population is used). |
678.84 |
=VAR.S(A2:A11) |
The variance, using the VAR.S function, which assumes only a sample of the population is tested. The result is different from VAR.P. |
754.27 |